簡單的兩執行緒程式 Example Code: 宣告一個返回Fibonacci 數列元素值的子程式, 並讓主執行緒與一個子執行緒分別平行運算該數值五次
threads.py

• import threading
• import time
• import numpy as np
• def FibonacciN(N):
•     Fibonacci=[0,1]
•     for i in range(N):
•         Fibonacci = np.append(Fibonacci, Fibonacci[-2]+Fibonacci[-1])
•     return Fibonacci[-1]
• def MultiJobs(): #the function to test the threading
•     for i in range(3):
•         N=50
•         print("Child thread:", i, ',', N+2, 'th elements of Fibonacci is ', FibonacciN(N))
• threadNum = 3 #using three threads
• threads = []
•     for i in range(threadNum):
•         threads.append(threading.Thread(target = MultiJobs))
•         threads[i].start()
• for i in range(3):
•     N=50
•     print("main thread :", i, ',', N+2, 'th elements of Fibonacci is ', FibonacciN(N))
• for i in range(threadNum):
•     threads[i].join()
• print("Done.")

Note and Comments

• import threading
• import time
• import numpy as np
• def FibonacciN(N):
•     Fibonacci=[0,1]
•     for i in range(N):
•         Fibonacci = np.append(Fibonacci, Fibonacci[-2]+Fibonacci[-1])
•     return Fibonacci[-1]
• def MultiJobs(): #the function to test the threading
•     for i in range(3):
•         N=50
•         print("Child thread:", i, ',', N+2, 'th elements of Fibonacci is ', FibonacciN(N))
• threadNum = 3 #using three threads
• threads = []
•     for i in range(threadNum):
•         threads.append(threading.Thread(target = MultiJobs))
•         threads[i].start()
• for i in range(3):
•     N=50
•     print("main thread :", i, ',', N+2, 'th elements of Fibonacci is ', FibonacciN(N))
• for i in range(threadNum):
•     threads[i].join()
• print("Done.")

result

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